Answer:
21m^2
Explanation:
First, we can find the areas of the two large rectangles.
A=lw
A=2*6
A=12m^2
A=lw
A=2*5
A=10m^2
Now, we can find the area of the small square where the two rectangles overlap. We can tell that the side lengths of the square are all equal to 1 (we know this because the side lengths of the rectangles are 1 less on one side).
A=lw
A=1*1
A=1m^2
Now, we can subtract 1m^2 from either of the two rectangles’ area we solved for earlier.
12m^2-1m^2
=11m^2
Then, we can add this area to the area of the other rectangle.
11m^2+10m^2
=21m^2
I hope this helps!
