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Find an equation of the straight line that is perpendicular to y=2x+1 and passes through the point (-2,5)

Sagot :

clarch19

Answer:

y = -1/2x + 4

Step-by-step explanation:

to answer this question you need to find the slope and the y-intercept

to find the slope of a line that is perpendicular to another line you take the opposite and reciprocal of the slope of the first line

in this case the slope of the initial line is 2; therefore, the opposite reciprocal is -1/2

knowing slope ('m') = -1/2 and having the point (-2, 5) can give us the y-intercept of the new line; we start with:

y = mx + b  and then plug the values in so find the y-intercept ('b')

5 = (-1/2)(-2) + b

5 = 1 + b

b = 4

put it all together:  y = -1/2x + 4

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