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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Sagot :

Answer:

[tex]\displaystyle \tan A=\frac{4}{3}[/tex]

Step-by-step explanation:

Funciones Trigonométricas

La identidad principal en trigonometría es:

[tex]sen^2A+cos^2A=1[/tex]

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

[tex]cos^2A=1-sen^2A[/tex]

Sustituyendo:

[tex]\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2[/tex]

[tex]\displaystyle cos^2A=1-\frac{16}{25}[/tex]

[tex]\displaystyle cos^2A=\frac{25-16}{25}[/tex]

[tex]\displaystyle cos^2A=\frac{9}{25}[/tex]

Tomando raíz cuadrada:

[tex]\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}[/tex]

La tangente se define como:

[tex]\displaystyle \tan A=\frac{sen\ A}{cos\ A}[/tex]

Substituyendo:

[tex]\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}[/tex]

[tex]\displaystyle \tan A=\frac{4}{3}[/tex]