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The following chemical reaction takes place in aqueous solution: SnSO 4 (aq)+2 NaOH(aq) Sn(OH) 2 (s)+Na 2 SO 4 (aq) Write the net tonic equation for this reaction.

Sagot :

Eduard22sly

The net ionic equation for the reaction between SnSO₄ and NaOH is:

Sn²⁺(aq) + 2OH¯(aq) —> Sn(OH)₂(s)

We'll begin by writing the dissociation equation for SnSO₄ and NaOH.

SnSO₄(aq) —> Sn²⁺(aq) + SO₄²¯(aq)

NaOH(aq) —> Na⁺(aq) + OH¯(aq)

In solution, the reaction will proceed as follow:

SnSO₄(aq) + NaOH(aq) —>

Sn²⁺(aq) + SO₄²¯(aq) + Na⁺(aq) + OH¯(aq) —> Sn(OH)₂(s) + Na⁺(aq) + SO₄²¯(aq)

Cancel the spectator ions (i.e Na⁺ and SO₄²¯) and write 2 before OH¯ to obtain the net ionic equation.

Sn²⁺(aq) + 2OH¯(aq) —> Sn(OH)₂(s)

Learn more: https://brainly.com/question/12913128

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