Answered

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Mixture Problem
1. How much water should be added to 8 mL of 6% saline solution to reduce the concentration to 4%?

Sagot :

menaliparikh

Answer:

Amount of active ingredient is 0.04(8+x)= 0.32+0.4x

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EQUATION:

active ingre. + active ingre. = active ingre

0.48 + 0 = 0.32 + 0.04x

0.16 = 0.04x

x=4ML (amount of water that must be added)

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