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hi find the distance in the coordanite plane between the two points and show ur work


1 (5, -8) and (5,2)


2 (-8, -2) and (7, -2)


3 (9, 10) and (9, -2)


4 (11 , 6) and (-7, 6)


Sagot :

Answer:

The distance between (5, -8) and (5,2) is: d = 10 units

Step-by-step explanation:

Note: I will solve the first question as the procedure solution for the remaining questions is exactly the same.

Given the points

  • (5, -8)
  • (5,2)

Determining the distance between (5, -8) and (5,2)

[tex]d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]

substitute (x₁, y₁) = (2, 3) and (x₂, y₂) = (2, -5)

   [tex]=\sqrt{\left(5-5\right)^2+\left(2-\left(-8\right)\right)^2}[/tex]

   [tex]=\sqrt{\left(5-5\right)^2+\left(2+8\right)^2}[/tex]

   [tex]=\sqrt{0+10^2}[/tex]

   [tex]=\sqrt{10^2}[/tex]

   [tex]=10[/tex]  units

Therefore, the distance between (5, -8) and (5,2) is: d = 10 units