Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
AE - 3, EB - 2, EC - 5
Step-by-step explanation:
Use the Pythagorean theorem and you'll find that these are the answers.
I'll answer problem 19
=======================================================
Part (a)
The tickmarks on segments DE and DC indicate they are the same length. We're also told that |DC| = |DE| = 5.
So DE is also 5 cm long. Triangle DAE is a right triangle with the 90 degree angle at angle A. Let x be the length of segment AE.
We'll use the pythagorean theorem to find x
a^2 + b^2 = c^2
(AE)^2 + (AD)^2 = (DE)^2
x^2 + 4^2 = 5^2
x^2 + 16 = 25
x^2 = 25-16
x^2 = 9
x = sqrt(9)
x = 3
Segment AE is 3 cm long
=======================================================
Part (b)
For any rectangle, the opposite sides are parallel and the same length. This means AB = DC = 5 cm.
We found earlier that AE = 3 cm, so,
AE+EB = AB
3+EB = 5
EB = 5-3
EB = 2
Segment EB is 2 cm long
=======================================================
Part (c)
We know that AD = BC = 4 cm, because the opposite sides are the same length.
Earlier in part (b), we found that segment EB was 2 cm long.
Triangle EBC is a right triangle with legs EB = 2 and BC = 4. Let's apply the pythagorean theorem to find EC. Let y = EC.
a^2 + b^2 = c^2
(EB)^2 + (BC)^2 = (EC)^2
2^2 + 4^2 = y^2
4 + 16 = y^2
20 = y^2
y^2 = 20
y = sqrt(20)
y = sqrt(4*5)
y = sqrt(4)*sqrt(5)
y = 2*sqrt(5)
y = 4.4721359
As an exact value, EC is sqrt(20) or 2*sqrt(5) cm long.
As an approximate value, EC is roughly 4.4721359 cm long.
I would ask your teacher if you should use the exact or approximate value.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.