Answered

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An area of a wall is 50 in. wide and 35 in. high. Will a mirror with a 62 in. diagonal fit in it? Identify the correct explanation.

Sagot :

clarch19

Answer:

yes

Step-by-step explanation:

i used the pythagorean theorem and used 50 and 35 as the legs and the diagonal as the hypotenuse

35² + 50² = c²

c² = 3725

c = [tex]\sqrt{3725}[/tex], which is 61.03

since 61.03 is less than 62" then it should fit in

No, Given Mirror will be not fit in the wall.

Here, we use Pythagoras theorem

Base is 50 inch , Height is 35 inch

Now we have to find hypotenuse

[tex]h^{2} =(50)^{2}+(35)^{2} \\\\h^{2}=2500+1225=3725\\\\h=\sqrt{3725}=61.03[/tex]

Since, Diagonal length of wall is 61.03 inch which is less than mirror diagonal length.

Therefore, mirror is not fit in the wall.

Learn more:

https://brainly.com/question/13391411

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