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Hi. I need help with this question :

Question : y is such that
[tex]4y - 7 \leqslant 3y[/tex] and
[tex]3y \leqslant 5y + 8[/tex]:
I). What range of values satisfies both inequalities ?
II). Hence, express
[tex]4y - 7 \leqslant 3y \leqslant 5y + 8[/tex]
in the form of
[tex]a \leqslant y \leqslant b[/tex]
where a and b are both integers.

Please show workings.

​

Sagot :

Answer:

-4≤y≤7

Step-by-step explanation:

4y-3y≤7

y≤7

and

3y-5y≤8

-2y≤8

y≥-4

so, -4≤y≤7

sqdancefan

9514 1404 393

Answer:

  -4 ≤ y ≤ 7

Step-by-step explanation:

Solve the inequalities separately, then identify the intersection of the solution sets.

4y -7 ≤ 3y

  y -7 ≤ 0 . . . . . . . subtract 3y

  y ≤ 7 . . . . . . . . . add 7

3y ≤ 5y +8

  0 ≤ 2y +8 . . . . . . subtract 3y

  -8 ≤ 2y . . . . . . . . . subtract 8

  -4 ≤ y . . . . . . . . . . divide by 2

The intersection of the sets y ≤ 7 and -4 ≤ y is given by ...

  -4 ≤ y ≤ 7

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