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Sagot :
The probability of all correct is [tex]\frac{1}{4}[/tex] or 25%.
Given that,
- There are 3 questions given i,e a =3.
- Each question had four choices i.e b = 4.
- We need to find the probability of all three correct.
According to the situation, calculation of given data are as follows,
Probability of all correct = [tex]\frac{a}{(a \times b )}[/tex]
By putting the value, we get,
Probability = [tex]\frac{3}{(3 \times 4) }[/tex]
= [tex]\frac{3}{12}[/tex]
By simplifying the fraction, we get,
Probability = [tex]\frac{1}{4}[/tex] or 0.25 or 25%.
Learn more about probability: https://brainly.com/question/24361544
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