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Sagot :
I'm here buddy,
so, let's take the value of the two bags with equal weight as x.
= x + x + (x + [tex]\frac{6}{5}[/tex]) = [tex]\frac{27}{4}[/tex]
= 3x + [tex]\frac{6}{5}[/tex] = [tex]\frac{27}{4}[/tex]
= 3x = [tex]\frac{27}{4}[/tex] - [tex]\frac{6}{5}[/tex]
( let's take the LCM of 4 and 5 = 20
= 3x = [tex]\frac{135}{20}[/tex] - [tex]\frac{24}{20}[/tex]
= 3x = [tex]\frac{111}{20}[/tex]
= x = [tex]\frac{111}{20}[/tex] ÷ [tex]\frac{3}{1}[/tex] = [tex]\frac{111}{20}[/tex] × [tex]\frac{1}{3}[/tex] = [tex]\frac{37}{20}[/tex]
So, the weight of the equal bags are [tex]\frac{37}{20}[/tex] and the weight of the third bag ( heavy one ) is [tex]\frac{37}{20}[/tex] + [tex]\frac{6}{5}[/tex] = [tex]\frac{37}{20}[/tex] + [tex]\frac{24}{20}[/tex] = [tex]\frac{61}{20}[/tex]
1st bag = [tex]\frac{37}{20}[/tex] kg
2nd bag = [tex]\frac{37}{20}[/tex] kg
3rd bag = [tex]\frac{61}{20}[/tex] kg
Hope it helps...
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