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2. A spy uses a telescope to track a rocket launched vertically from a launch pad 6 km away. The rocket travels upwards at a velocity of 21.6 km per minute. Find the rate of change of the distance between the spy and the rocket when the rocket is 8 km in the air. Answer: 17.28 km/mim

NEED HELP ASAP

Sagot :

billgkgk

Answer:

The rate of change in distance between the spy and the rocket is 10.8 km/min,

or about 180 m/sec.

Step-by-step explanation:

At "Time=0" the rocket is 6km from the spy.

The rocket travels vertically 8km in about 0.37 minutes, calculated by 8km÷21.6km/min.

At that point, the rocket is 10 km from the spy., calculated by 6²+8²=10²

The difference is 4 kiilometers over 0.37minutes, about 22.2 seconds

Divide Distance by Time to get Rate:

4km/0.37min = 10.8 km/min

That is about 180 meters per second.

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