JaelynW
Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How? (2x^2 - 3x - 4)(x + 7)
​

Sagot :

Answer:

[tex]2 {x}^{3} + 11{x}^{2} - 25x - 28[/tex]

Step-by-step explanation:

Using foil method, Multiply the first term

[tex]2 {x}^{2} \times x = 2 {x}^{3} [/tex]

Next, Multiply the Outer term in each parenthesis. (2x^2 and 7

[tex] 2 {x}^{2} \times 7 = 14 {x}^{2} [/tex]

[tex] 2 {x}^{2} \times 7 = 14 {x}^{2} \: \: \: 3x \times - x = - 3x[/tex]

Then, Multiply the Inner Terms (-3x,-4,7) in each parenthesis

[tex] - 3x \times 7 = - 21x[/tex]

[tex] - 4 \times x = - 4x[/tex]

Then multiply the last term (-4 and 7).

[tex] - 4 \times 7 = - 28[/tex]

Combine it you have

[tex]2 {x}^{3} + 14 {x}^{2} - 3 {x}^{2} - 21x - 4x - 28[/tex]

which simplify to

[tex]2 {x}^{3} + 11 {x}^{2} - 25x - 28[/tex]

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.