Answer:
[tex]1. 3x+21 = 6x-60\\or, 6x-3x = 21+60 [Being~corresponding~angles]\\or, 3x = 81\\or, x = 27.\\Equations: 3x+21=6x-60\\Value ~of ~x = 27\\Angle ~measure = (3x+21), (6x-60) = 3(27)+21,6(27)-60 = 102,102\\[/tex]
[tex]2. 12x - 18 = 8x+10 [Being~vertically~opposite~angles]\\or, 12x - 8x = 18+10\\or, 4x = 28\\or, x = 7\\Equations: 12x-18 = 8x+10\\Value~ of~ x: 7\\Angle ~measure: (12x-18),(8x+10) = 66,66\\[/tex]
[tex]3. Have~a~look~at~the~figure.\\Here, y = 3x+9 [Being~ vertically ~opposite ~angles]\\Also, y+5x+3 = 180^{o} [ Being~cointerior~angles]\\or, 3x^{o}+9^{o}+5x^{o}+3^{o}=180^{o}\\or, 8x^{o}+12^{o}=180^{0}\\or, 8x^{o} = 168^{o}\\or, x = 21^{o}\\So, 3x+9 = 3(21)+0 = 72^{o} ~and ~5x+3 = 5(21)+3 = 108^{o}\\Equations: y = 3x +9, y+5x+3=180^{o}\\Value ~of~ x: 21^{o}\\Angle ~measure: 72^{o},108^{o}[/tex]
[tex]4.~~~~ (3x+10)^{o}+(3x-28)^{o} = 180^{o} [Being~cointerior~angles]\\or, ~~~6x -18^{o} = 180^{o}\\or, 6x=198^{o}\\or, x = 33^{o}\\So, 3x+10 = 3(33)+10 = 109^{o}~and~3x-28 = 3(33)-28 = 71^{o}\\Equations: 3x+10+3x-28 = 180^o\\Value~ of~ x: 33^o\\Angle~measure: 109^o,71^o\\[/tex]
[tex]5. Solution,\\12x+15 = 15x [Being ~alternate~angles]\\or, 15x-12x = 15\\or, 3x=15\\or, x = 5^{o}\\So, 12x+15 = 12(5)+15 = 75^o = 15x\\Equations: 12x+15=15x\\Value~of~x: 5^o\\Angle ~measure: 75^o,75^o[/tex]
