Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Suppose the half-life of a certain radioactive substance is 20 days and there are 50g present initially.
a)
Write an equation that models this situation.
b)
How much radioactive substance is remaining after 12 days?
c)
Find the time when there will be 1g of the substance remaining.

Sagot :

Answer:

a)   10(5g + 2r)   weight loss over time

b)   20/12 = 1.66667 = 50 / 1.67 = 29.999 gm = 5(6g -1/50)  or  5(5 + g) = 30g

c) 30g = 12 days = 3/5   therefore 5/5 -3/5 = 2/5  = 2/5 x 50 (g) = 20g in 8 days lost

8/20 = 0.4  loss each day 50g - 0.8g = 20-2 = 18 days.

Step-by-step explanation:

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.