Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How many grams of ammonia are present in 5.0 L of a 0.050 M solution

Sagot :

samueladesida43

Answer:

4.25g

Explanation:

Molar concentration or molarity can be calculated thus;

Molarity (M) = number of moles (n) ÷ volume (V)

According to the provided information in this question, Volume = 5.0L, M = 0.050 M

number of moles = molarity × volume

n = 0.050 × 5

n = 0.25moles

Number of moles in a substance = mass (M) ÷ molar mass (MM)

Molar mass of ammonia (NH3) = 14 + 1(3)

= 17g/mol

Mass = moles × molar mass

Mass (g) = 0.25 × 17

Mass = 4.25g

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.