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How many grams of O2 are formed from 13.34 moles of KClO3? Provide your final answer rounded to two decimal places.

2 KClO3 → 2 KCl + 3 O2

Sagot :

maacastrobr

Answer:

640.32 g

Explanation:

2KClO₃ → 2KCl + 3O₂

First we convert KClO₃ moles to O₂ moles, using the stoichiometric coefficients:

  • 13.34 mol KClO₃ * [tex]\frac{3molO_{2}}{2molKClO_{3}}[/tex] = 20.01 mol O₂

Then we convert O₂ moles to grams, using its molar mass:

  • 20.01 mol O₂ * 32 g/mol = 640.32 g

So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.

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