adamaljanabi07
Answered

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Kira ,Charlie , and Miguel have a total of $105 in their wallets . Kira has $9 less than Miguel. Charlie has 4 times what Miguel has . How much does each have ?

Sagot :

LadyStrange

Let the money with Miguel be x.

Then :

Money with Kira = x - 9

Money with Charlie = 4x

Total money in their wallet = $105

This can be written in an equation as :

[tex] = \tt \: x + x - 9 + 4x = 105[/tex]

[tex] = \tt2x + 4x - 9 = 105[/tex]

[tex] = \tt 6x - 9 = 105[/tex]

[tex] = \tt6x = 105 + 9[/tex]

[tex] = \tt6x = 114[/tex]

[tex] = \tt x = \frac{114}{6} [/tex]

[tex] = \tt x = 19[/tex]

Which means :

Money with Miguel = $19

Money with Kira :

= 19 - 9

Thus, Kira has $10 in her wallet.

Money with Charlie :

= 4 × 19

= 76

Thus, Charlie has $76 in his wallet.

Therefore,

  • Money with Kira = $10
  • Money with Charlie = $76
  • Money with Miguel = $19
ItzDevilKing

Answer:

Let the money with Miguel be x.

Then :

Money with Kira = x - 9

Money with Charlie = 4x

Total money in their wallet = $105

This can be written in an equation as :

= \tt \: x + x - 9 + 4x = 105=x+x−9+4x=105

= \tt2x + 4x - 9 = 105=2x+4x−9=105

= \tt 6x - 9 = 105=6x−9=105

= \tt6x = 105 + 9=6x=105+9

= \tt6x = 114=6x=114

= \tt x = \frac{114}{6}=x=

6

114

= \tt x = 19=x=19

Which means :

Money with Miguel = $19

Money with Kira :

= 19 - 9

Thus, Kira has $10 in her wallet.

Money with Charlie :

= 4 × 19

= 76

Thus, Charlie has $76 in his wallet.

Therefore,

Money with Kira = $10

Money with Charlie = $76

Money with Miguel = $19

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