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The specific heat of water is 4.2j/g ºC how much heat is required to raise the temperature of 100 g of water by 5 ºC

Sagot :

Answer:

116,823 J

Explanation:

formula : q=m C delta T

q = heat = unknown

mass = 100 g

C = specific heat = 4.2 J/K*g

delta T = temperture in Kelvins: 5 + 273.15 = 278.15 K

q = (100 g) ( 4.2 J/K*g) (278.15 K) = 116,823 J

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