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What is the theoretical yield of SO3 produced by 8.96 g of S?

Sagot :

Answer: Theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]

[tex]\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles[/tex]

The balanced chemical equation is:  

[tex]2S+3O_2\rightarrow 2SO_3[/tex]  

According to stoichiometry :

2 moles of [tex]S[/tex] produce =  3 moles of [tex]SO_3[/tex]

Thus 0.28 moles of [tex]S[/tex] will produce=[tex]\frac{3}{2}\times 0.28=0.42moles[/tex]  of [tex]SO_3[/tex]  

Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g[/tex]

Thus theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g

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