Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Given:
The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).
To find:
The fourth vertex of the parallelogram.
Solution:
Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).
We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.
Midpoint formula:
[tex]Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]
Two diagonals of ABCD are AC and BD.
Midpoint of AC = Midpoint of BD
[tex]\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)[/tex]
[tex]\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)[/tex]
On comparing both sides, we get
[tex]\dfrac{4+a}{2}=\dfrac{-1}{2}[/tex]
[tex]4+a=-1[/tex]
[tex]a=-1-4[/tex]
[tex]a=-5[/tex]
And,
[tex]\dfrac{5+b}{2}=\dfrac{3}{2}[/tex]
[tex]5+b=3[/tex]
[tex]b=3-5[/tex]
[tex]b=-2[/tex]
Therefore, the coordinates of fourth vertex are (-5,-2).
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
