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Answered

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simplify the product.
[tex]10\sqrt{12x^{3} } . 2\sqrt{6x^{5} }[/tex]
full calculations please!!

Sagot :

madethisfortwitch1

Answer:

[tex]120x^4\sqrt{2}[/tex]

Step-by-step explanation:

First we need to break down the numbers in the radicals into its factors

so

12= 3*2*2

x³=x*x*x

Which means we have

[tex]10\sqrt{3*2*2*x*x*x}=20x\sqrt{3x}[/tex]

and

[tex]2\sqrt{2*3*x*x*x*x*x} =2x^{2} \sqrt{6x}[/tex]

Because the radicand (the small number that goes up top) are the same we can just mulitply the two from here

which means we have

[tex](20x*2x^2)\sqrt{3x*6x}=40x^3\sqrt{18x^2} \\\sqrt{18x^2}=\sqrt{2*3*3*x*x} =3x\sqrt{2} \\=120x^4\sqrt{2}[/tex]

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