fxvuu
Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

simplify the product.
[tex]10\sqrt{12x^{3} } . 2\sqrt{6x^{5} }[/tex]
full calculations please!!


Sagot :

Answer:

[tex]120x^4\sqrt{2}[/tex]

Step-by-step explanation:

First we need to break down the numbers in the radicals into its factors

so

12= 3*2*2

x³=x*x*x

Which means we have

[tex]10\sqrt{3*2*2*x*x*x}=20x\sqrt{3x}[/tex]

and

[tex]2\sqrt{2*3*x*x*x*x*x} =2x^{2} \sqrt{6x}[/tex]

Because the radicand (the small number that goes up top) are the same we can just mulitply the two from here

which means we have

[tex](20x*2x^2)\sqrt{3x*6x}=40x^3\sqrt{18x^2} \\\sqrt{18x^2}=\sqrt{2*3*3*x*x} =3x\sqrt{2} \\=120x^4\sqrt{2}[/tex]