Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Answer:
Approximately 92 mm.
Explanation:
Object's distance, u = 110 mm = 11 cm
focal length of the mirror = 5 cm
Image distance, v = ?
To determine the image distance, apply the mirror's formula;
[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]
[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{f}[/tex] - [tex]\frac{1}{u}[/tex]
= [tex]\frac{1}{5}[/tex] - [tex]\frac{1}{11}[/tex]
= [tex]\frac{11-5}{55}[/tex]
[tex]\frac{1}{v}[/tex] = [tex]\frac{6}{55}[/tex]
⇒ v = [tex]\frac{55}{6}[/tex]
= 9.166667
v = 9.2 cm
The image distance is 92 mm.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.