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(x-h)^2+(y-k)^2=r^2
Derive standard form of an equation of a circle with center C(5,2) and radius r=4, using the Pythagorean theorem.

Sagot :

abidemiokin

Answer:

(x-2)^2 + (y - 5)^2 = 16

Step-by-step explanation:

Given the standard form of an equation of a circle

(x-h)^2+(y-k)^2=r^2

If (h, k) = (5,2) and r = 4

Substitute

(x-2)^2 + (y - 5)^2 = 4^2

(x-2)^2 + (y - 5)^2 = 16

Hence the required equation is (x-2)^2 + (y - 5)^2 = 16

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