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Halla 2 enteros cuyo producto sea 210 y uno de los enteros debe ser uno menos que el doble del otro​

Sagot :

danecortva
El ejercicio, se resuelve mediante un sistema de ecuaciones.

Llamemos a los enteros A y B.

1) A*B= 210.
2)B=(1+2A)

Sustituyendo 2 en 1

A*(1+2A)=210.

A+2A²-210= 0

Utilizaremos la siguiente ecuación:



Siendo a=2, b=1, c=-210

A₁=10
A₂= -10,5

Por lo que para B, tambien existen 2 resultados.

B₁= 21
B₂=-20
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