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Sagot :
Answer:
58.333 days
Explanation:
using "scale" can solve the problem
we know that Jessie take 7 days to save 6$
lets pretend "=" as "can get"
lets say:
7
d
y
=
6
$
7
d
y
⋅
k
=
6
$
⋅
k
by the way
6
$
⋅
k
is
50
$
, so k is
50
6
7
d
y
⋅
k
=
6
$
⋅
k
7
d
y
⋅
50
6
=
6
$
⋅
50
6
7
d
y
⋅
50
6
=
50
$
58.333
...
.
d
y
=
50
$
another way is to use a right triangle,
let the base has the width 7, each unit along the y-axis means "1 day"
let the height has the height 6, each unit along the x-axis means "1$"
now extend the height to 50 units, you will find your new big triangle has a base of 58.3...... units
this is because the tangent of the angle is the same
graph{y = 6/7x [-28.13, 103.57, -3.1, 62.7]}
58.333 days
Explanation:
using "scale" can solve the problem
we know that Jessie take 7 days to save 6$
lets pretend "=" as "can get"
lets say:
7
d
y
=
6
$
7
d
y
⋅
k
=
6
$
⋅
k
by the way
6
$
⋅
k
is
50
$
, so k is
50
6
7
d
y
⋅
k
=
6
$
⋅
k
7
d
y
⋅
50
6
=
6
$
⋅
50
6
7
d
y
⋅
50
6
=
50
$
58.333
...
.
d
y
=
50
$
another way is to use a right triangle,
let the base has the width 7, each unit along the y-axis means "1 day"
let the height has the height 6, each unit along the x-axis means "1$"
now extend the height to 50 units, you will find your new big triangle has a base of 58.3...... units
this is because the tangent of the angle is the same
graph{y = 6/7x [-28.13, 103.57, -3.1, 62.7]}
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