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A load of 600N is lifted using a first class lever applying an effort of 350N. If the distance between the fulcrum and the effort is 60cm and the distance between the load and the fulcrum is 30cm, calculate it's efficiency

Sagot :

ohiekulous

Answer:

The efficiency of the machine is 85.5%

Explanation:

Mechanical advantage = Load/Effort

= 600/350 = 1.71

Velocity ratio = distance moved by effort/distance moved by load

= 60/30 = 2

Efficiency = (M.A/V.R) × 100%

= (1.71/2) × 100

= 0.855 × 100

= 85.5%

The efficiency of the machine is 85.5%

Given:

Load= 600N

Effort= 350N

distance between the fulcrum and the effort = 60cm

distance between the load and the fulcrum = 30cm

The formula of the mechanical advantage(MA) of a lever is given as

Mechanical advantage = Load/Effort

Mechanical advantage = [tex]\frac{600}{350} =1.71[/tex]

Velocity ratio = distance moved by effort/distance moved by load

Velocity ratio = [tex]\frac{60}{30} =2[/tex]

Efficiency = (M.A/V.R) × 100%

= (1.71/2) × 100

= 0.855 × 100

Efficiency= 85.5%

Learn more:

brainly.com/question/23693991

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