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A 150 g sample of brass at 90.0 degrees Celsius is placed in a calorimeter cup that contains 230 g of water at 20.0 degrees Celsius. Disregard the absorption of heat by the cup and calculate the final temperature of the brass and water. Specific heat of water = 4.18 J/gC, specific heat of brass=0.380 J/gC.

Sagot :

Answer:

for brass

mass m1 =150g

t1=90°c

specific heat of brass s1=0.380 J/gC.

for water

t2=20°c

mass m2=230g

Specific heat of water s2= 4.18 J/gC,

Explanation:

we have

Q1=Q2

m1s1{t-t1)=m2s2(t2-t)

150×0.380(t-90)=230×4.18(20-t)

57t-5130=961.4×20-961.4t

57t +961.4t=19228+5130

1018.4t=24358

t=24358/1018.4=23.91=24°c is final temperature

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