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Subtract the cube root of the product of x and 3y from the square of the sum of a and b.

Sagot :

Zezima

Answer:

[tex](a+b)^{2}- \sqrt[3]{x . 3y}[/tex]

Step-by-step explanation:

Subtract the cube root of the product of x and 3y from the square of the sum of a and b.  

A = The square of the sum of a and b is  [tex](a+b)^{2}[/tex]

B = The cube root of the product of x and 3y is  [tex]\sqrt[3]{x . 3y}[/tex]

They want us to subtract B from A so B - A, therefore the following.

[tex](a+b)^{2}- \sqrt[3]{x . 3y}[/tex]  

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