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12 cos theta minus 16 sin theta is equal to zero find 2 sin theta + cos theta​

Sagot :

Answer:

2sinθ + cosθ = 2

Step-by-step explanation:

12 cos θ - 16 sinθ = 0

=> 3 cos θ -4 sin θ = 0

=> tanθ = 3/4

let P = 3x

B = 4x

=> H= 5x

=> sinθ = P/H = 3/5

cosθ = B/H = 4/5

2sinθ + cosθ

= 2× 3/5 + 4/5

= 6/5+4/5

= 10/5

= 2

=> 2sinθ + cosθ = 2

Answer:

2sinθ + cosθ = 2

Step-by-step explanation:

12 cos θ - 16 sinθ = 0

=> 3 cos θ -4 sin θ = 0

=> tanθ = 3/4

let P = 3x

B = 4x

=> H= 5x

=> sinθ = P/H = 3/5

cosθ = B/H = 4/5

2sinθ + cosθ

= 2× 3/5 + 4/5

= 6/5+4/5

= 10/5

= 2