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Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Sagot :

lublana

Answer:

[tex]f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}[/tex]

Step-by-step explanation:

We are given that

[tex]f(x)=tan(x)-\frac{2}{x}[/tex]

[tex]g(x)=x^2+8[/tex]

We have to find [tex]f(x)\times g(y)[/tex]

To find the value of [tex]f(x)\times g(y)[/tex] we will multiply f(x) by g(y)

[tex]g(y)=y^2+8[/tex]

Now,

[tex]f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)[/tex]

[tex]f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)[/tex]

[tex]f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}[/tex]

Hence,

[tex]f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}[/tex]

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