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Find the product of the monomial and the polynomial:
−3a·(7a^2−4)

Sagot :

lublana

Answer:

[tex]-21a^{3}+12a[/tex]

Step-by-step explanation:

We are given that

[tex]-3a\cdot (7a^2-4)[/tex]

We have to find the product .

To find the product we will multiply -3a with each term given in the bracket

[tex]-3a(7a^2)-3a(-4)[/tex]

[tex]-21a^{1+2}+12a[/tex]

By using the formula

[tex]a^{x}\cdot a^{y}=a^{x+y}[/tex]

[tex]-21a^{3}+12a[/tex]

Hence,

[tex]-3a\cdot (7a^2-4)=-21a^{3}+12a[/tex]

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