At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
4, 8, 16.
Step-by-step explanation:
Let the three numbers in GP be [tex]r, ra, ra^2[/tex], where [tex]a \ne 0[/tex]. We are given that [tex]r + ra + ra^2 = 28[/tex] and [tex]r \cdot ra \cdot ra^2 = r^3a^3 = 512[/tex], the latter of which gives [tex]ra = \sqrt[3]{512} = 8[/tex]. So substituting this into the former equation gives [tex]\frac{8}{a} + 8 + 8a = 28[/tex] or
[tex]8 + 8a + 8a^2 = 28a\\2a^2 + 2a + 2 = 7a\\2a^2 - 5a + 2 = 0\\(2a-1)(a-2) = 0\\a = \frac{1}{2} \vee a = 2[/tex]
And this gives our answer directly.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
