Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
156
Step-by-step explanation:
We are given that
Length of cardboard, l=69.9 cm
Width of cardboard, b=24 cm
Height of cardboard, h=36.01 cm
Length of book, l=22 cm
Width of book, b=19.5 cm
Thickness of book, h=0.9 cm
Volume of cuboid=lbh
Using the formula
Volume of cardboard=[tex]69.9\times 24\times 36.01 cm^3[/tex]
Volume of one book=[tex]22\times 19.5\times 0.9 cm^3[/tex]
Number pf exercise book=[tex]\frac{volume\;of\;cardboard}{volume\;of;one\;book}[/tex]
Number of exercise book=[tex]\frac{69.9\times 24\times 36.01}{22\times 19.5\times 0.9}[/tex]
Number of exercise book=156
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.