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a sample of nitrogen gas occupies 1.55l at 27.0c and 1.00 atm what will the volume be at -100.0c and the same pressure

Sagot :

ardni313

V₂=0.894 L

Further explanation

Given

V₁=1.55 L

T₁=27 + 273 = 300 K

P₁=1 atm

T₂=-100+273 = 173 K

Required

The final volume(V₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Input the value :

V₂=V₁T₂/T₁

V₂=1.55 x 173/300

V₂=0.894 L

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