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Find the distance d (P1, P2) between the points P, and P2.
P1 = (-2,5); P2 = (4,0)
(P4, P2) - (Type an exact answer, using radicals as needed.)

Sagot :

lublana

Answer:

[tex]\sqrt{61}[/tex] units

Step-by-step explanation:

We are given that

[tex]P_1=(-2,5)[/tex]

[tex]P_2=(4,0)[/tex]

We have to find the distance d (P1, P2) between the points P, and P2

We know that

Distance between  two points (x1,y1) and (x2,y2)  i

=[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

The distance d (P1, P2) between the points P, and P2

=[tex]\sqrt{(4-(-2))^2+(0-5)^2}[/tex]

The distance d (P1, P2) between the points P, and P2

[tex]=\sqrt{(4+2)^2+(-5)^2}[/tex]

The distance d (P1, P2) between the points P, and P2

=[tex]\sqrt{6^2+25}[/tex]

The distance d (P1, P2) between the points P, and P2

=[tex]\sqrt{61}[/tex] units

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