Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.


Helpppp! This assignment is due in 15 minutes . Click the photo attached.

Helpppp This Assignment Is Due In 15 Minutes Click The Photo Attached class=

Sagot :

jacobEwing

Answer:

1: 6.637e-13 N

2: 6.637e-09 N

3: 1.335e-08 N

4: 1.335e-08 N

5: 1.456e-06 N

6: 5.839e-07 N

7: 6.673e-11 N

I'd suggest double checking these if you can.

Explanation:

Each of these you can answer by plugging the numbers into the equation

[tex]F = G\frac{m_1 m_2}{r^2}[/tex]

G is the gravitational constant 6.673×10⁻¹¹ N m² / kg²

So the first one would be:

[tex]F = 6.673 \times 10^{-11} \frac{Nm^2}{kg^2} \times\frac{1kg\times 1kg}{(10m)^2}\\F = 6.673 \times 10^{-11} N \times\frac{1}{100}\\F = 6.673 \times 10^{-13}N[/tex]

I'm not going to run through showing all calculations for the rest, as you're in a rush, so to whip through them

2: 6.637e-09 N

3: 1.335e-08 N

4: 1.335e-08 N

5: 1.456e-06 N

6: 5.839e-07 N

7: 6.673e-11

Pardon the lack of superscript, I just punched these into a python console to calculate them.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.