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Helpppp! This assignment is due in 15 minutes . Click the photo attached.


Helpppp This Assignment Is Due In 15 Minutes Click The Photo Attached class=

Sagot :

Answer:

1: 6.637e-13 N

2: 6.637e-09 N

3: 1.335e-08 N

4: 1.335e-08 N

5: 1.456e-06 N

6: 5.839e-07 N

7: 6.673e-11 N

I'd suggest double checking these if you can.

Explanation:

Each of these you can answer by plugging the numbers into the equation

[tex]F = G\frac{m_1 m_2}{r^2}[/tex]

G is the gravitational constant 6.673×10⁻¹¹ N m² / kg²

So the first one would be:

[tex]F = 6.673 \times 10^{-11} \frac{Nm^2}{kg^2} \times\frac{1kg\times 1kg}{(10m)^2}\\F = 6.673 \times 10^{-11} N \times\frac{1}{100}\\F = 6.673 \times 10^{-13}N[/tex]

I'm not going to run through showing all calculations for the rest, as you're in a rush, so to whip through them

2: 6.637e-09 N

3: 1.335e-08 N

4: 1.335e-08 N

5: 1.456e-06 N

6: 5.839e-07 N

7: 6.673e-11

Pardon the lack of superscript, I just punched these into a python console to calculate them.