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Sagot :
Answer:
- 39 multiples
Step-by-step explanation:
Consider AP:
- 105, 110, ..., 295
As multiples of 5 between 100 and 300
The first term is 105, the common difference is 5, the last term is 295.
Use the nth term formula:
- 105 + 5(n - 1) = 295
- 5(n - 1) = 190
- n - 1 = 190/5
- n - 1 = 38
- n = 39
Answer:
Solution given:
first term [a]=100
last term[l]=300
common difference [d]=5
second term[b]=100+5=105
now
we have
l=a+(n-1)d
substituting value
300=100+(n-1)5
300-100=(n-1)5
200/5=n-1
40=n-1
n=40+1
there are 41 multiple in between 100 and 300/including it but no including its 41-2=39 multiple
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