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write the equation of a line that passes through the point ( -1, 5) and has a slope of -7

Sagot :

xKelvin

Answer:

[tex]y=-7x-2[/tex]

Step-by-step explanation:

We can use the point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope and (x₁, y₁) is a point.

Let (-1, 5) be (x₁, y₁) and our slope m is -7. By substitution:

[tex]y-(5)=-7(x-(-1))[/tex]

Distribute:

[tex]y-5=- 7 x - 7[/tex]

Adding 5 to both sides gives us our equation:

[tex]y=-7x-2[/tex]

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