YujiC
Answered

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what is the initial value of the function:
f(x)=3/2(2)^x

Sagot :

clarch19

Answer:

the initial value -- f(0) -- results in a value of 1.5

Step-by-step explanation:

f(0) = [tex]\frac{3}{2}[/tex] · [tex]2^{x}[/tex]     (any value raised to the power of zero equals one)

f(0) = [tex]\frac{3}{2}[/tex] · 1

f(0) = 3/2 or 1.5
It’s NONE. You can use symbolab
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