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A ball is thrown into the air from a height of 4 feet at time t=0. The function that models this situation is h(t)=-16t^2+63t+4. What will be the height of the ball after 2 seconds?

Sagot :

cosmickid287

Answer:

66 feet

Step-by-step explanation:

We know that the t in the equation represents the time. So, substitute 2 for the t in the function and simplify to find the height after 2 seconds:

[tex]h(t) = -16t^2+63t+4\\h(2) = -16(2)^2+63(2)+4\\h(2) = -16(4)+126+4\\h(2) = -64 + 126+4\\h(2) = 66[/tex]

Thus, the height would be 66 feet.

Answer:

The answer would be 66 feet.

Step-by-step explanation:

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