Answered

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Suppose () = 46%; ( and ) = 10%; and ( or ) = 62% Find (Not ). Can this really be a probability? If not, explain why not.

Sagot :

MrRoyal

Answer:

[tex]P(E) = 26 \%[/tex]

Step-by-step explanation:

Given

[tex]P(F) = 46\%[/tex]

[tex]P(E\ and\ F) = 10\%[/tex]

[tex]P(E\ or\ F) = 62\%[/tex]

Required

Find P(E)

In probability:

[tex]P(E\ and\ F) = P(E) + P(F) - p(E\ or\ F)[/tex]

Substitute the right values

[tex]10\% = P(E) + 46\% - 62\%[/tex]

[tex]10\% = P(E) -16 \%[/tex]

Collect Like Terms

[tex]P(E) = 10\% +16 \%[/tex]

[tex]P(E) = 26 \%[/tex]

It is a probability because all probabilities are within the range 0 to 100%

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