Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
We have a data set with 6 whole numbers:
{A, B. C, D, E, F}
The median, in this case, will be the mean of the two middle numbers, C and D.
Median = (C + D)/2 = 40
We also know that the difference between the largest and the smallest number is 21, where the largest number is F and the smallest number is A, then:
F - A =21.
And the mean will be:
Now we want to take the largest possible numbers such that we end having the largest mean of the whole set, then we can start by taking:
(C + D)/2 = 40
Here we can just take:
C = 39
D = 41
Now our set is:
{A, B, 39, 41, E, F}
Now, A and B should be the largest possible whole numbers (and they must be smaller than 39
The two options are:
B = 38
A = 37
Now our set is:
{37, 38, 39, 41, E, F}
Now, remember that:
F - A = 21
F - 37 = 21
F = 21 + 37 = 58
Then our set will be:
{37, 38, 39, 41, E, 58}
And for E, we should pick the largest number that we could.
In this case, the only restrictions we have for E are that it must be larger than 41, and smaller than 58.
The largest number that meets those conditions is the number 57.
Then our set will be:
{37, 38, 39, 41, 57, 58}
And the mean of this set is:
Mean = (37 + 38 + 39 + 41 + 57 + 58)/6 = 45
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.