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The sum of 3 consecutive integers is 78. What is the integer closest to zero?

Sagot :

xKelvin

Answer:

25

Step-by-step explanation:

Let n be the first integer.

Then the second integer will be (n + 1).

And the third will be (n + 2).

The sum is 78. Therefore:

[tex]n+(n+1)+(n+2)+78[/tex]

Solve for n. Combine like terms:

[tex]3n+3=78[/tex]

So:

[tex]3n=75[/tex]

Therefore:

[tex]n=25[/tex]

Therefore, the first integer is 25.

So our sequene is 25, 26, and 27.

The integer closest to zero will thus be 25.

Therefore the first integer is 25
So our sequence is 25, 26 and 27 respectively
The integer closest to zero will thus be 25.
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