Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The length of a rectangle is two times its width. Find the area if its perimeter is 7 1/3

Sagot :

Let x be the width

width = x

Length is twice its width

length = 2x

Perimeter = length + width + length + width

Perimeter = x + 2x + x + 2x = 6x

Given that perimeter = 7 1/3

6x = 7 1/3

x = 7 1/3 ÷ 6 = 1 2/9

So width = 1 2/9

Length = 1 2/9 x 2 = 2 4/9

Area = length x width

Area = 1 2/9 x 2 4/9

Area = 2 80/81 square cm