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How many moles is 287.7 grams of Iridium (Ir)?

Sagot :

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Answer:

1.497 mol Ir

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

287.7 g Ir

Step 2: Identify Conversions

[PT] Molar Mass of Ir - 192.22 g/mol

Step 3: Convert

  1. Set up:                                 [tex]\displaystyle 287.7 \ g \ Ir(\frac{1 \ mol \ Ir}{192.22 \ g \ Ir})[/tex]
  2. Multiply/Divide:                   [tex]\displaystyle 1.49672 \ mol \ Ir[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

1.49672 mol Ir ≈ 1.497 mol Ir

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf About \ 1.497 \ mol \ Ir }}[/tex]

Explanation:

To convert from grams to moles, we must the molar mass of iridium, which can be found on the Periodic Table.

  • Ir: 192.22 g/mol

Use the molar mass as a ratio.

[tex]\frac{ 192.22 \ g \ Ir}{ 1 \ mol \ Ir}[/tex]

Multiply by the given number of grams: 287.7

[tex]287.7 \ g Ir *\frac{ 192.22 \ g \ Ir}{ 1 \ mol \ Ir}[/tex]

Flip the fraction so the grams of Iridium will cancel.

[tex]287.7 \ g Ir *\frac{1 \ mol \ Ir }{ 192.22 \ g \ Ir}[/tex]

[tex]287.7 *\frac{1 \ mol \ Ir }{ 192.22 }[/tex]

[tex]\frac {287.7 \ mol \ Ir }{192.22} \\[/tex]

Divide.

[tex]1.49672251 \ mol \ Ir[/tex]

The original measurement has 4 significant figures, so we must round our answer to 4 sig figs as well. For the answer we calculated, that is the thousandth place.

The 7 in the ten thousandth place tells us to round the 6 up to a 7.

[tex]1.497 \ mol \ Ir[/tex]

There are about 1.497 moles of iridium in 287.7 grams.

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