Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A field is a rectangle with a perimeter of 1240 feet. The length is 400 feet more than the width. Find the width and length of the rectangular field.
The width


A Field Is A Rectangle With A Perimeter Of 1240 Feet The Length Is 400 Feet More Than The Width Find The Width And Length Of The Rectangular Field The Width class=

Sagot :

Answer:  The length is 510 and the width is 110.

Step-by-step explanation:

To find the area of a rectangle, you will have to add the 2 times the length plus 2 times the width because  a rectangle have 4 sides. Two widths and two  lengths.

You can now use the formula  P= 2l + 2w  

were P is the perimeter , l is the length, and w is the width.

the length is 400 more than the width, so we can represent that by the equation,  l = w + 400  

And now we know that the width is w.

So now we will input the perimeter, length, and into the formula to solve for w.

1240 = 2(w + 400) + 2w

1240 = 2w + 800 + 2w

1240 = 4w + 800

-800            -800

   440 = 4w

    w = 110

L= 110 + 400

L = 510  

Check :

1240 = 2(510) + 2(110)

1240 = 1020 + 220

1240 = 1240

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.