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what is the equation of the line that passes through the point (3,2) and has a slope of -5/3

Sagot :

Answer is y = -5/3x + 7

Y = mx + c

Given: m = -5/3

Y = -5/3x + c

Put in the coordinates (3, 2)

2 = -5/3 (3) + c

2 = -5 + c

Taking -5 on the other side

C = 2 + 5

C = 7

Therefore the equation of line is:

Y = -5/3x + 7

Answer:

y=-5/3x+7

Step-by-step explanation:

equation of line=

y=mx+c

insert given values in the equation

2=(-5/3)x3+c

2=-5+c

c=5+2

c=7

Equation of line=

y=-5/3x+7