Answer:
[tex] \huge \boxed{ \tt i)1.6} \\ \huge \boxed{ \tt ii)4.3} \\ \huge \boxed{ \tt iii)8.3} \\ \huge \boxed{ \: \: \: \: \tt iv)9.2 \: \: \: }[/tex]
Step-by-step explanation:
to understand this
you need to know about:
- square root
- finding square root by division method
- converting decimal to a fraction
- PEMDAS
tips and formulas:
tips for finding square root by division method
- Group the digits in pairs, starting with the digit in the units place
- Think of the largest number whose square is equal to or just less than the first period. Take this number as the divisor and also as the quotient.
- Subtract the product of the divisor and the quotient from the first period and bring down the next period to the right of the remainder.
- the new divisor is obtained by taking two times the quotient and annexing with it a suitable digit which is also taken as the next digit of the quotient, chosen in such a way that the product of the new divisor and this digit is equal to or just less than the new dividend.
- Repeat steps till all the periods have been taken up
tips for converting decimal to a fraction
- Write down the decimal divided by 1
- Multiply both top and bottom by 10 for every number after the decimal point
- reduce the fraction
let's solve:
solve the square roots using division method:
the picture is attached
solve the square roots by converting decimals into fraction:
[tex] \tt i) \sqrt{2.56} \\ \tt \sqrt{ \frac{256}{100} } \\ \tt \sqrt{ \frac{1 {6}^{2} }{ {10}^{2} } } \\ \tt\frac{16}{10} \\ \tt \: 1.6[/tex]
[tex] \tt ii) \sqrt{18.49} \\ \tt \sqrt{ \frac{1849}{100} } \\ \tt\sqrt{ \frac{ {43}^{2} }{ {10}^{2} } } \\ \tt \frac{43}{10} \\ \tt 4.3[/tex]
[tex] \tt iii) \sqrt{ 68.89} \\ \tt \sqrt{ \frac{6889}{100} } \\ \tt \sqrt{ \frac{ {83}^{2} }{ {10}^{2} } } \\ \tt \frac{83}{10} \\ \tt 8.3[/tex]
[tex] \tt iv) \sqrt{84.64} \\ \tt\sqrt{ \frac{8464}{100} } \\ \tt\sqrt{ \frac{ {92}^{2} }{ {10}^{2} } } \\ \tt \frac{92}{10} \\ \tt9.2[/tex]
