Given:
A figure of a right angle triangle.
To find:
The value of x.
Solution:
In a right angle triangle,
[tex]\tan \theta = \dfrac{Opposite}{Adjacent}[/tex]
In the given triangle,
[tex]\tan (30^\circ) = \dfrac{x}{7}[/tex]
[tex]\dfrac{1}{\sqrt{3}}=\dfrac{x}{7}[/tex]
On multiplying both sides by 7, we get
[tex]\dfrac{7}{\sqrt{3}}=x[/tex]
Therefore, the value of x is [tex]x=\dfrac{7}{\sqrt{3}}[/tex].
